96`sqrt3 sin(pi/48) cos(pi/48) cos(pi/24) cos(pi/12) cos(pi/6)` has the value

Explanation

To solve the expression \( 96\sqrt{3} \sin\left(\frac{\pi}{48}\right) \cos\left(\frac{\pi}{48}\right) \cos\left(\frac{\pi}{24}\right) \cos\left(\frac{\pi}{12}\right) \cos\left(\frac{\pi}{6}\right) \), we can follow these steps:

### Step 1: Simplify the Expression
We start with the expression:
\[ f = 96\sqrt{3} \sin\left(\frac{\pi}{48}\right) \cos\left(\frac{\pi}{48}\right) \cos\left(\frac{\pi}{24}\right) \cos\left(\frac{\pi}{12}\right) \cos\left(\frac{\pi}{6}\right) \]

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