In any `triangleABC`, prove that `(sqrt(sinA)-sqrt(sinB))/(sqrt(sinA) + sqrt(sinB)) = (a+b-2sqrt(ab))/(a-b)`
[Hint : `(a-b)^(2) = a^(2)+b^(2)-2ab`]

Explanation

To prove that

\[ \frac{\sqrt{\sin A} - \sqrt{\sin B}}{\sqrt{\sin A} + \sqrt{\sin B}} = \frac{a + b - 2\sqrt{ab}}{a - b} \]

for any triangle \(ABC\), we can use the sine rule and some algebraic manipulation.

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