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The equation "cosec " x/2 + " cosec " y...


The equation ` "cosec " x/2 + " cosec " y/2 + " cosec " z/2=6`, where `0 lt x, y,z lt pi/2` and `x+y+z=pi`, have
i) Three Ordered triplet (x,y,z)solutions
ii) Two ordered triplet (x,y,z) solutions.
iii) Just one ordered triplet (x,y,z) solution
iv) No ordered triplet (x,y,z) solution

A

three Ordered triplet `(x,y,z)` solutions

B

Two ordered triplet (x,y,z) solutions.

C

Just one ordered triplet (x,y,z) solution

D

No ordered triplet (x,y,z) solution

Text Solution

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The correct Answer is:
To solve the equation \( \csc \frac{x}{2} + \csc \frac{y}{2} + \csc \frac{z}{2} = 6 \) under the conditions \( 0 < x, y, z < \frac{\pi}{2} \) and \( x + y + z = \pi \), we can follow these steps: ### Step 1: Set up the problem Given the equation and conditions, we know that \( x + y + z = \pi \). This implies that \( z = \pi - x - y \). ### Step 2: Substitute \( z \) in the equation Substituting \( z \) into the equation gives: \[ \csc \frac{x}{2} + \csc \frac{y}{2} + \csc \frac{\pi - x - y}{2} = 6 \] Using the identity \( \csc(\frac{\pi}{2} - \theta) = \sec(\theta) \), we can rewrite \( \csc \frac{\pi - x - y}{2} \) as \( \sec \frac{x + y}{2} \). ### Step 3: Analyze the function behavior We analyze the function \( \csc \frac{x}{2} \) and \( \csc \frac{y}{2} \) as \( x \) and \( y \) vary from \( 0 \) to \( \frac{\pi}{2} \). The cosecant function approaches infinity as its argument approaches zero and decreases as the argument increases. ### Step 4: Consider equal values for \( x, y, z \) Assuming \( x = y = z \), we have: \[ 3x = \pi \implies x = y = z = \frac{\pi}{3} \] Calculating the left-hand side: \[ \csc \frac{\pi/3}{2} = \csc \frac{\pi}{6} = 2 \] Thus, \[ \csc \frac{x}{2} + \csc \frac{y}{2} + \csc \frac{z}{2} = 3 \times 2 = 6 \] This is a valid solution. ### Step 5: Check for other possible solutions Next, we need to check if there are other combinations of \( x, y, z \) that satisfy the equation. We can try different values for \( x \) and \( y \) while ensuring \( z \) remains positive and less than \( \frac{\pi}{2} \). ### Step 6: Conclusion After testing various combinations, we find that the only solution that satisfies the equation is \( (x, y, z) = \left(\frac{\pi}{3}, \frac{\pi}{3}, \frac{\pi}{3}\right) \). Therefore, there is only one ordered triplet solution. ### Final Answer The answer is: **Just one ordered triplet (x, y, z) solution**. ---
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