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Check whether the following statements a...

Check whether the following statements are true and false
(i) 101 is a prime number or a composite number
(ii) A hexagon is 6 sided polygon or rectangle
(iii) `sqrt(157)` is a rational number or an interger
(iv) Two lines intersect at a point or are parellel

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Here ''OR'' is exclusive and component statements are
p : 101 is a prime number (True)
q : 101 is a compositive number (False)
Here, p is true and q is false so compound statement is true
(ii) Here "OR" is exclusive and component statements are
p : A hexagonal is 6 sided polygon. (True)
q : hexagonal is a rectangle. (False)
Here, one component statement is true, so compound statement is true.
(iii) Here inclusive "OR" is used, and component statements are
p : `sqrt(157)` is a rational number. (False)
q `sqrt(157)` is a integer. (False)
Here both p and q are false, so compound statement is false.
(iv). Here exclusive "OR" is used and the compound statements are
p : Two llnes intersect at a point. (True)
r : Two lines are parallel. (True)
Here when p is true r is false and when r is true p is false . So the compound statement is true
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AAKASH INSTITUTE ENGLISH-MATHEMATICAL REASONING-Assignment (SECTION-D) (Assertion-Reason Type Questions)
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  2. Let p be the statement "It rains"! and q be the statement "It is cold"...

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  3. If p, q, r be anY three. statements STATEMENT-1 : pvv(q^^r)hArr(pvvq...

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  4. STATEMENT-1 : The converse of p rArr q " is " q rArr p and STAT...

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  5. STATEMENT-1 : ~(prArrq)=p^^~q and STATEMENT-2 : p rArr q = ~p ...

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  6. STATEMENT-1 : (phArrq)=~ p hArr q and STATEMENT-2 : (phArrq) ...

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  7. Let p be the statement "x is divisible b, 4" and q be the statement "x...

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  8. STATEMENT-1 : The inverse of (p^^~q) rArrr " is "~pvvqrArr ~r and ...

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  9. STATEMENT-1 : If (p^^~r)rArr(qvvr) is false and q and r are false , th...

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  10. STATEMENT-1 : p hArr ~q is true, when pis false and q is true. and ...

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  11. STATEMENT-1 : (p^^~q)^^(~p^^q) and STATEMENT-2 : (pvv~q) vv (~p...

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  12. STATEMENT-1 : (p rArr q) hArr (~q rArr~p) and STATEMENT-2 : p rA...

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  13. STATEMENT-1 : (p rArr ~q) ^^ (~q rArr q) is a contradication and ...

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  14. STATEMENT-1 : The dual statement of "xis a perfect square or xis a pri...

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  15. STATEMENT-1 : [p^^(pvvq)]vv[q^^(qvvp)]=pvvq and STATEMENT-2 : p...

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  16. STATEMENT-1 : ~(phArrq)=~phArrq=phArr~q and STATEMENT-2 : (phArr...

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