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Verify by the method of contradiction p : If a,`b in Z` , then `a^2-4b ne 2`

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To verify the statement \( P: \text{If } a, b \in \mathbb{Z}, \text{ then } a^2 - 4b \neq 2 \) using the method of contradiction, we will follow these steps: ### Step 1: Assume the Opposite We start by assuming the opposite of the statement we want to prove. So, we assume: \[ a^2 - 4b = 2 \] ...
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AAKASH INSTITUTE ENGLISH-MATHEMATICAL REASONING-Assignment (SECTION-D) (Assertion-Reason Type Questions)
  1. Verify by the method of contradiction p : If a,b in Z , then a^2-4b ne...

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  2. Let p be the statement "It rains"! and q be the statement "It is cold"...

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  3. If p, q, r be anY three. statements STATEMENT-1 : pvv(q^^r)hArr(pvvq...

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  4. STATEMENT-1 : The converse of p rArr q " is " q rArr p and STAT...

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  5. STATEMENT-1 : ~(prArrq)=p^^~q and STATEMENT-2 : p rArr q = ~p ...

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  6. STATEMENT-1 : (phArrq)=~ p hArr q and STATEMENT-2 : (phArrq) ...

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  7. Let p be the statement "x is divisible b, 4" and q be the statement "x...

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  8. STATEMENT-1 : The inverse of (p^^~q) rArrr " is "~pvvqrArr ~r and ...

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  9. STATEMENT-1 : If (p^^~r)rArr(qvvr) is false and q and r are false , th...

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  10. STATEMENT-1 : p hArr ~q is true, when pis false and q is true. and ...

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  11. STATEMENT-1 : (p^^~q)^^(~p^^q) and STATEMENT-2 : (pvv~q) vv (~p...

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  12. STATEMENT-1 : (p rArr q) hArr (~q rArr~p) and STATEMENT-2 : p rA...

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  13. STATEMENT-1 : (p rArr ~q) ^^ (~q rArr q) is a contradication and ...

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  14. STATEMENT-1 : The dual statement of "xis a perfect square or xis a pri...

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  15. STATEMENT-1 : [p^^(pvvq)]vv[q^^(qvvp)]=pvvq and STATEMENT-2 : p...

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  16. STATEMENT-1 : ~(phArrq)=~phArrq=phArr~q and STATEMENT-2 : (phArr...

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