If a number is multiple of 5 then its end digit wiil be 5 or 0.
Contrarositive of above statement is

Options

A. If a number is not multiple of 5, then it$ end digit will not be 5 or 0.
B. If end digit of a number is not 5 or 0 then it will not be multiple of 5.
C. If a number is not multiple of 5, then its end digit will be 5 or 0
D. If end digit of of number is 5 or 0, then the number will be 5.

Answer

To find the contrapositive of the given statement, we will follow these steps:

1. **Identify the original statement**: The original statement is "If a number is a multiple of 5, then its end digit will be 5 or 0." We can denote this as:
- Let \( p \): "A number is a multiple of 5."
- Let \( q \): "Its end digit will be 5 or 0."

2. **Write the contrapositive**: The contrapositive of a statement of the form "If \( p \), then \( q \)" is "If not \( q \), then not \( p \)". This can be expressed as:
- If \( \neg q \), then \( \neg p \).

3. **Negate \( q \)**: The negation of \( q \) ("Its end digit will be 5 or 0") is:
- \( \neg q \): "Its end digit will not be 5 or 0."

4. **Negate \( p \)**: The negation of \( p \) ("A number is a multiple of 5") is:
- \( \neg p \): "It is not a multiple of 5."

5. **Combine the negations**: Now, we can combine these negations into the contrapositive statement:
- "If its end digit is not 5 or 0, then it is not a multiple of 5."

Thus, the contrapositive of the given statement is:
**If its end digit is not 5 or 0, then it is not a multiple of 5.**