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Find the domain of defintion of the function `f(x) = sqrt(x^(2) - 3x + 2)`.

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To find the domain of the function \( f(x) = \sqrt{x^2 - 3x + 2} \), we need to ensure that the expression under the square root is non-negative. This means we need to solve the inequality: \[ x^2 - 3x + 2 \geq 0 \] ### Step 1: Factor the quadratic expression We start by factoring the quadratic expression \( x^2 - 3x + 2 \). We look for two numbers that multiply to \( 2 \) (the constant term) and add up to \( -3 \) (the coefficient of \( x \)). The numbers \( -1 \) and \( -2 \) satisfy these conditions. ...
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AAKASH INSTITUTE ENGLISH-RELATIONS AND FUNCTIONS -Try Yourself
  1. Let A = {1, 2, 3, 4}. Examine which of the following relations is a f...

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  2. Find the domain of definition of the function f(x) = sqrt(x^(2) - 5x +...

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  3. Find the domain of defintion of the function f(x) = sqrt(x^(2) - 3x + ...

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  4. Find the domain of f(x) = (x^(2)-9)/(x-3)

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  5. Find the domain of (1)/(1-x^(2))

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  6. Find the domain f(x) = sqrt(3x - 5).

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  7. Find the domain of f(x) = sqrt(x-11).

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  8. Find the domain of f(x) = (8-x)/(x-8).

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  9. Find the domain of f(x) = (x^(2)-36)/(x+6)

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  10. Find the domain of definition of the function f(x) = sqrt(a^(2) - x^(2...

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  11. Find the domain of definition of the function f(x) = sqrt(64 - x^(2)).

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  12. Find the domain of the function f(x) = (x^(2)+5x+1)/(x^(2)-6x + 8).

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  13. Find the domain of the function f(x) = (x-1)/(x^(2) + 5x +6).

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  14. Find the range: (i) f(x) = 1+x (ii) f(x) = (1)/(x) , x != 0

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  15. Find the range : (i) f(x) = 2x^(2) (ii) f(x) = -x^(2)

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  16. Find the domain of the function y = (x)/(1-x^(2)).

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  17. Find the range of the function y = (x^(2) - 1)/(x-1), x != 1.

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  18. Define the function f : R rarr R by y = f(x) = x^(4), x in R. What is ...

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  19. Define the function f : R rarr R by y = f(x) = x^(5), x in R. What is...

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  20. Given the function f(x) = x^(2) + 2x + 5. Find f(-1), f(2), f(5).

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