If `a ** b = 4a^(2) + 6b^(2)` be a binary operations on Q, then verify that `**` is not commutative.

Explanation

To verify that the binary operation defined by \( a ** b = 4a^2 + 6b^2 \) is not commutative, we need to check whether \( a ** b \) is equal to \( b ** a \) for all \( a, b \in \mathbb{Q} \).

### Step-by-step Solution:

1. **Define the operation**:
We have the operation defined as:
\[
a ** b = 4a^2 + 6b^2
...