Home
Class 12
MATHS
Let f : N rarr N be defined as f(x) = 2x...

Let f : `N rarr N` be defined as f(x) = 2x for all `x in N`, then f is

A

Onto

B

Invertible

C

One-one

D

Many one

Text Solution

AI Generated Solution

The correct Answer is:
To determine the properties of the function \( f: \mathbb{N} \to \mathbb{N} \) defined by \( f(x) = 2x \) for all \( x \in \mathbb{N} \), we will analyze whether the function is one-to-one (injective), onto (surjective), and if it is invertible. ### Step-by-step Solution: 1. **Understanding the Function**: The function is defined as \( f(x) = 2x \). This means for every natural number \( x \), the output is double that number. 2. **Checking if the Function is One-to-One (Injective)**: A function is one-to-one if different inputs produce different outputs. - Let's assume \( f(a) = f(b) \) for some \( a, b \in \mathbb{N} \). - This means \( 2a = 2b \). - Dividing both sides by 2 gives us \( a = b \). - Since \( a \) must equal \( b \), the function is injective. 3. **Checking if the Function is Onto (Surjective)**: A function is onto if every element in the codomain (range) has a pre-image in the domain. - The codomain here is \( \mathbb{N} \). - The outputs of the function \( f(x) = 2x \) are all even natural numbers (2, 4, 6, ...). - However, the odd natural numbers (1, 3, 5, ...) do not have pre-images in \( \mathbb{N} \) because there is no natural number \( x \) such that \( f(x) \) would yield an odd number. - Therefore, the function is not onto. 4. **Conclusion about Invertibility**: A function is invertible if it is both one-to-one and onto. - Since \( f \) is one-to-one but not onto, it cannot be invertible. 5. **Final Classification**: Based on the analysis, we can conclude: - The function \( f(x) = 2x \) is one-to-one (injective) but not onto (surjective) and therefore not invertible. ### Summary of Properties: - **One-to-One (Injective)**: Yes - **Onto (Surjective)**: No - **Invertible**: No
Promotional Banner

Topper's Solved these Questions

  • RELATIONS AND FUNCTIONS

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section - B) Objective Type Questions (one option is correct)|86 Videos
  • RELATIONS AND FUNCTIONS

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section - C) Objective Type Questions (More than one option are correct)|17 Videos
  • RELATIONS AND FUNCTIONS

    AAKASH INSTITUTE ENGLISH|Exercise Try Yourself|70 Videos
  • PROBABILITY

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT SECTION-J (aakash challengers questions)|11 Videos
  • SEQUENCES AND SERIES

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (SECTION - J) Aakash Challengers|11 Videos

Similar Questions

Explore conceptually related problems

Let f : R rarr R be defined by f(x) = x^(2) - 3x + 4 for all x in R , then f (2) is equal to

If f: N to N defined as f(x)=x^(2)AA x in N, then f is :

Let f : N rarr N be a function defined as f(x) = 4x^(2) + 12x + 15 is invertible (where S is range of f). Find the inverse of f and hence find f^(-1)(31) .

Show that the function f: N rarr N defined by f(x)= 2x + 3 , where x in N , is not bijective.

Let f : N to N : f(x) =2 x for all x in N Show that f is one -one and into.

Let f:N->N be defined by f(x)=x^2+x+1,x in N . Then f(x) is

Let f : R - {2} rarr R be defined as f(x) = (x^2 - 4)/(x-2) and g: R rarr R be defined by g(x) = x + 2. Find whether f = g or not.

Let f : N rarr R be the function defined by f(x) = (2x-1)/(2) and g : Q rarr R be another function defined by g(x) = x + 2. Then (gof) ((3)/(2)) is

Let f,g: Rvec be defined by f(x)=2x+1a n d g(x)=x^2-2 for all x in R , respectively. Then, find gofdot

Let f, g : R rarr R be defined respectively by f(x) = 2x + 3 and g(x) = x - 10. Find f-g.

AAKASH INSTITUTE ENGLISH-RELATIONS AND FUNCTIONS -Assignment (Section - A) Objective Type Questions (one option is correct)
  1. Function f :R->R,f(x) = x|x| is

    Text Solution

    |

  2. domain of f(x) = (x^(2))/(1-x^(2)), is

    Text Solution

    |

  3. Let f : N rarr N be defined as f(x) = 2x for all x in N, then f is

    Text Solution

    |

  4. Let A={1,2,3,4,5,6}dot Define a relation R on set A by R={(x , y): y=x...

    Text Solution

    |

  5. Let f(x) = [x] and g(x) = x - [x], then which of the following functi...

    Text Solution

    |

  6. Function f : R rarr R, f(x) = x + |x|, is

    Text Solution

    |

  7. Function f : [(pi)/(2), (3pi)/(2)] rarr [-1, 1], f(x) = sin x is

    Text Solution

    |

  8. Function f[(1)/(2)pi, (3)/(2)pi] rarr [-1, 1], f(x) = cos x is

    Text Solution

    |

  9. If f : R rarr R, f(x) = sin^(2) x + cos^(2) x, then f is

    Text Solution

    |

  10. If function f(x) = (1+2x) has the domain (-(pi)/(2), (pi)/(2)) and co-...

    Text Solution

    |

  11. The function f : (0, oo) rarr [0, oo), f(x) = (x)/(1+x) is

    Text Solution

    |

  12. If f(x) = x/(x-1)=1/y then the value of f(y) is

    Text Solution

    |

  13. gof exists, when :

    Text Solution

    |

  14. If f : R rarr R, f(x) = x^(2) + 2x - 3 and g : R rarr R, g(x) = 3x - 4...

    Text Solution

    |

  15. If f : R rarr R, f(x) = x^(2) - 5x + 4 and g : R^(+) rarr R, g(x) = lo...

    Text Solution

    |

  16. If f : R - {1} rarr R, f(x) = (x-3)/(x+1), then f^(-1) (x) equals

    Text Solution

    |

  17. If function f : R rarr R^(+), f(x) = 2^(x), then f^(-1) (x) will be eq...

    Text Solution

    |

  18. If f(x) = 2 sinx, g(x) = cos^(2) x, then the value of (f+g)((pi)/(3))

    Text Solution

    |

  19. The graph of the function y = log(a) (x + sqrt(x^(2) + 1)) is not sym...

    Text Solution

    |

  20. If the function f:[1,\ oo)->[1,\ oo) defined by f(x)=2^(x(x-1)) is inv...

    Text Solution

    |