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Show that the function f given by f(x) ...

Show that the function f given by ` f(x) ={{:( x^(2)+5, if x ne 0), (3, if x = 0):}` is not continuous at x=0

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The function is defined at x =0 its value at x =0 is 3 when `x ne 0`, the function is given by a polynomial, Hence,
` underset(x to 0) lim f(x) = underset(x to 0)lim x^(2)+5 =0^(2) + 5=5 `
Since the limit does not coincide with f(0) , the function is not continuous at x =0, As well, x =0 is the only point of discontinuity .
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