Find the tension in the strings AC and BC shown in figure.

Explanation

FBD of point C:
C is at equilibrium , so
` T_(2) sin 60^(@) = 100 N`
` rArr T_(2) = 100/(sin60^(@) )N`
` 200 /sqrt(3) `N
Again , `T_(1) = T_(2) cos 60^(@)`
` = 200/sqrt(3) xx 1/2`
` = 100/sqrt(3)`N