The pressure of a given mass of a gas filled in a vessel of volume V at constant temperature is reduced to `1//3` rd of its initial value. Calculate the percentage change in its volume.

Explanation

Applying Boyle's
`P_(1)V_(1)=P_(2)V_(2)`
`because_(2)=(1)/(3)P_(1)`
Substituting the values in equation, we get
`P_(1)V_(1)=(1)/(3)P_(1)V_(2)`
then, `V_(2)=3V_(1)`
change in volume `DeltaV=V_(2)-V_(1)`
`=2V_(1)`
Percentage change `=(DeltaV)/(V)xx100`
`=(2V_(1))/(V_(1))xx100`
`=200%`