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For a molecule of an ideal gas n=3xx10^(...

For a molecule of an ideal gas `n=3xx10^(8)cm^(-3)` and mean free path is `10^(-2)` cm. Calculate the diameter of the molecule.

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To solve the problem, we will use the formula for the mean free path \( L \) of gas molecules, which is given by: \[ L = \frac{1}{\sqrt{2} \pi n d^2} \] where: - \( L \) is the mean free path, ...
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