Calculate the diameter of one molecule of an ideal gas having number density `2xx10^(8)cm^(-3)` and mean free path of the molecule is `10^(-8)cm`.

Explanation

To calculate the diameter of one molecule of an ideal gas given the number density and mean free path, we can use the formula for mean free path:

\[ \lambda = \frac{1}{\sqrt{2} \pi d^2 n} \]

Where:
- \(\lambda\) is the mean free path,
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