Home
Class 12
PHYSICS
A gas is found to obey the law p^(2)V=co...

A gas is found to obey the law `p^(2)V`=constant. The initial temperature and volume are `T_(0)` and `V_(0)`. If the gas expands to a volume `3V_(0)`, then

A

`sqrt(3)T_(0)`

B

`sqrt(2)T_(0)`

C

`(T_(0))/(sqrt(3))`

D

`(T_(0))/(sqrt(2))`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • KINETIC THEORY

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section-C) Objective type questions (More than one option are correct)|9 Videos
  • KINETIC THEORY

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section-D) (Linked Comprehension Type Questions)|6 Videos
  • KINETIC THEORY

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section-A) Objective type questions (One option is correct)|49 Videos
  • GRAVITATION

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT SECTION - D (ASSERTION-REASON TYPE QUESTIONS)|15 Videos
  • LAWS OF MOTION

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (SECTION-D) (Assertion-Reason Type Questions)|15 Videos

Similar Questions

Explore conceptually related problems

A gas is found to obey the law P^(2)V = constant . The initial temperature and volume are T_(0) and V_(0) . If the gas expands to a volume 3 V_(0) , its final temperature becomes

A gas is found to be obeyed the law p^2V = constant . The initial temperature and volume are T_0 and V_0 . If the gas expands to a volume 3 V_0 , then the final temperature becomes.

During an experiment, an ideal gas is found to obey an additional law VP^2=constant, The gas is initially at a temperature T, and volume V. When it expands to a volume 2V, the temperature becomes…….

An ideal gas is found to obey the law V^2T = constant . The initial pressure and temperature are P_0 and T_0 . If gas expands such that its pressure becomes (P_0)/4 , then the final temperature of the gas will be

During an experiment, an ideal gas is found to obey a condition Vp^2 = constant. The gas is initially at a temperature (T), pressure (p) and volume (V). The gas expands to volume (4V).

During an experiment, an ideal gas is found to obey an additional law pV^(2) =constant. The gas is initially at a temperature T and volume V. Find the temperature when it expands to a volume 2V.

Suppose ideal gas equation follows VP^(3) = contant . Initial temperature and volume of the gas are T and V respectively. If gas expand to 27V temperature will become

Ten moles of a diatomic perfect gas are allowed to expand at constant pressure. The initial volume and temperature are V_0 and T_0 respectively. If 7/2RT_0 heat is transferred to the gas, then the final volume and temperature are

A mixture of ideal gas containing 5 moles of monatomic gas and 1 mole of rigid diatomic gas is initially at pressure P_0 volume V_0 and temperature T_0 . If the gas mixture is adiabatically compressed to a volume V_0//4 , then the correct statement(s) is(are) : (Given R is gas constant)

A monatomic ideal gas is contained in a rigid container of volume V with walls of total inner surface area A, thickness x and thermal conductivity K. The gas is at an initial temperature t_(0) and pressure P_(0) . Find the pressure of the gas as a function of time if the temperature of the surrounding air is T_(s) . All temperature are in absolute scale.