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The application of Gauss's theorem gives...

The application of Gauss's theorem gives rise to an easy evolution of electric field in the case of

A

A charged body of any geometrical configuration

B

A charged body of regular geometrical configuration

C

Revolving charged bodies

D

Charges forming dipoles

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To solve the question regarding the application of Gauss's theorem and its ease of evaluating the electric field for different geometrical configurations, we can follow these steps: ### Step 1: Understand Gauss's Theorem Gauss's theorem states that the electric flux (Φ) through a closed surface is equal to the charge (Q) enclosed by that surface divided by the permittivity of free space (ε₀): \[ \Phi = \frac{Q}{\epsilon_0} \] ### Step 2: Relate Electric Field to Flux The electric flux can also be expressed in terms of the electric field (E) and the surface area (S) of the closed surface: \[ \Phi = E \cdot S \] Where \(E\) is the electric field and \(S\) is the surface area through which the field lines pass. ### Step 3: Combine the Two Equations By combining the two equations from Steps 1 and 2, we can express the electric field as: \[ E \cdot S = \frac{Q}{\epsilon_0} \] From this, we can derive the electric field: \[ E = \frac{Q}{\epsilon_0 \cdot S} \] ### Step 4: Analyze Geometrical Configurations Now, we need to evaluate the types of geometrical configurations for which we can easily determine the surface area (S): - For **irregular shapes**: Determining the surface area is complex and often not straightforward. - For **regular geometrical shapes** (like spheres, cylinders, and cubes): The surface area can be calculated easily using standard formulas. ### Step 5: Conclusion Since Gauss's theorem allows for straightforward evaluation of the electric field primarily in cases where the surface area can be easily calculated, the best option is: - **Charged body of regular geometrical configuration** (like spheres, cylinders, or cubes). Thus, the answer to the question is that the application of Gauss's theorem gives rise to an easy evaluation of electric field in the case of a **charged body of regular geometrical configuration**. ### Final Answer The correct option is: **Charged body of regular geometrical configuration**. ---
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AAKASH INSTITUTE ENGLISH-ELECTRIC CHARGES AND FIELDS -ASSIGNMENT(SECTION-A) Objective Type Question
  1. Electric flux over a surface in an electric field

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  2. A cylinder is palced in a uniform electric field E with axis parallel ...

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  3. Electric charges q, q, -2q are placed at the corners of an equilateral...

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  4. A given charge is situated at a certain distance from an electric dipo...

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  5. An electric dipole placed in a non-uniform electric field experience i...

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  6. When an electric dipole is placed in a uniform electric field, a coupl...

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  7. An electric dipole placed in a nonuniform electric field experience

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  8. An electric dipole consists of two opposite charges of magnitude 1muC ...

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  9. A charge q is located at the centre of a cube. The electric flux throu...

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  10. A charge q is placed at the centre of the open end of a cylindrical ve...

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  11. Total electric flux coming out of a unit positive charge put in air is

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  12. A charged body has an electric flux phi associated with it. The body i...

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  13. The application of Gauss's theorem gives rise to an easy evolution of ...

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  14. the given figure shows two parallel plates A and B of change densities...

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  15. You are travelling in a car during a thunder storm. In order to protec...

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  16. The electric field inside a spherical shell of uniform surface charge ...

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  17. If the electric field intensity in a fair weather atmosphere is 100 V/...

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  18. A sphere of radius R has a uniform distribution of electric charge in ...

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  19. A nonconducting solid sphere of radius R is uniformly charged. The mag...

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  20. The electric field intensity at a distance 20cm from the centre of a u...

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