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In the given potentiometer circuit inte...


In the given potentiometer circuit internal resistance r of the cell of emf `epsilon` is to be determined when K is open balance point is obtained at `N_(1) , AN_(1) = 60 cm`. When K is close balance point is obtained at `N_(2) , AN_(2) = 50 cm ` , what is the value of r ?

Text Solution

Verified by Experts

If `l_(1) = 60 ` ( when K is off )
`l_(2) = 50 cm ` ( When K is on ) , then
`r= ((l_(1))/( l_(2))-1) R = (( 60)/(50)-1) 10 Omega `
`= (1)/(5) xx 10 Omega = 2Omega `
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