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In a potentiometer circuit, the emf of d...

In a potentiometer circuit, the emf of driver cell is 2V and internal resistance is `0.5 Omega `. The potentiometer wire is 1m long . It is found that a cell of emf 1V and internal resistance `0.5 Omega ` is balanced against 60 cm length of the wire. Calculate the resistance of potentiometer wire.

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To solve the problem step by step, we will follow these calculations: ### Step 1: Understand the given data - EMF of the driver cell (E1) = 2 V - Internal resistance of the driver cell (r1) = 0.5 Ω - Length of the potentiometer wire (L) = 1 m - EMF of the cell being measured (E2) = 1 V - Internal resistance of the cell being measured (r2) = 0.5 Ω ...
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