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Figure shows the circuit of a potentiome...

Figure shows the circuit of a potentiometer. The length of the potentiometer wire AB is 50 cm. The emf of the battery E, is 4 volt having negligible internal resistance. Values of resistances `R_(1)` and `R_(2)` are 15 ohm and 5 ohm respectively. When both the keys are open, he null point is obtained at a distance of 31.25 cm from end A but when both the keys are closed, the balance length reduces to 5 cm only `R_(AB) = 10 Omega `

Which of the following can be possible way to connect the batteries in the potentiometer setup above ?

A

Positive terminal of `E_(1)` and positive terminal of `E_(2)` connected to point A.

B

Negative terminal o f`E_(1)` and negative terminal of `E_(2)` connected to A

C

Positive terminal of `E_(1)` and negative terminal of `E_(2)` connected to A

D

Positive terminal of `E_(2)` and negative terminal of `E_(1)` connected to A

Text Solution

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The correct Answer is:
1, 2
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