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The amplitude of electric field at a di...

The amplitude of electric field at a distance `r` from a point source of power `P` is (taking 100% efficiency).

A

`sqrt((P)/(2pir^(2)cepsi_(0)))`

B

`sqrt((P)/(4pir^(2)cepsi_(0)))`

C

`sqrt((P)/(8pir^(2)cepsi_(0)))`

D

`(P)/(2pir^(2)cepsi_(0))`

Text Solution

AI Generated Solution

The correct Answer is:
To find the amplitude of the electric field \( E_0 \) at a distance \( r \) from a point source of power \( P \), we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Intensity**: The intensity \( I \) of the electromagnetic wave is defined as the power \( P \) per unit area. For a point source radiating uniformly in all directions, the area \( A \) at a distance \( r \) is given by the surface area of a sphere, which is \( 4\pi r^2 \). Thus, the intensity can be expressed as: \[ I = \frac{P}{A} = \frac{P}{4\pi r^2} \] 2. **Relating Intensity to Electric Field**: The intensity \( I \) is also related to the root mean square (RMS) value of the electric field \( E_{\text{rms}} \) by the formula: \[ I = \frac{E_{\text{rms}}^2}{c \mu_0} \] where \( c \) is the speed of light and \( \mu_0 \) is the permeability of free space. 3. **Expressing \( E_{\text{rms}} \)**: We know that the peak amplitude \( E_0 \) is related to the RMS value by: \[ E_{\text{rms}} = \frac{E_0}{\sqrt{2}} \] Therefore, we can rewrite the intensity in terms of \( E_0 \): \[ I = \frac{\left(\frac{E_0}{\sqrt{2}}\right)^2}{c \mu_0} = \frac{E_0^2}{2c \mu_0} \] 4. **Setting the Two Expressions for Intensity Equal**: Now, we can set the two expressions for intensity equal to each other: \[ \frac{P}{4\pi r^2} = \frac{E_0^2}{2c \mu_0} \] 5. **Solving for \( E_0^2 \)**: Cross-multiplying gives us: \[ E_0^2 = \frac{2c \mu_0 P}{4\pi r^2} \] Simplifying this, we have: \[ E_0^2 = \frac{c \mu_0 P}{2\pi r^2} \] 6. **Taking the Square Root**: Finally, we take the square root to find the amplitude of the electric field: \[ E_0 = \sqrt{\frac{c \mu_0 P}{2\pi r^2}} \] 7. **Substituting \( \mu_0 \)**: We know that \( c = \frac{1}{\sqrt{\mu_0 \epsilon_0}} \), thus \( \mu_0 = \frac{1}{c^2 \epsilon_0} \). Substituting this into our expression for \( E_0 \): \[ E_0 = \sqrt{\frac{P}{2\pi r^2 \epsilon_0 c}} \] ### Final Result: Thus, the amplitude of the electric field at a distance \( r \) from a point source of power \( P \) is given by: \[ E_0 = \sqrt{\frac{P}{2\pi r^2 \epsilon_0 c}} \]
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