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By how much percent does the speed of a ...

By how much percent does the speed of a satellite orbiting in circular orbit be increased so that it will escape from the gravitational field of the earth ?

A

`11.2 ` %

B

`41.4` %

C

`27.5` %

D

`34.4` %

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The correct Answer is:
To solve the problem of how much percent the speed of a satellite orbiting in a circular orbit must be increased to escape from the gravitational field of the Earth, we can follow these steps: ### Step 1: Understand the Kinetic and Potential Energy The kinetic energy (KE) of a satellite in a circular orbit is given by: \[ KE = \frac{1}{2} m v^2 \] where \( m \) is the mass of the satellite and \( v \) is its orbital speed. The gravitational potential energy (PE) of the satellite is given by: \[ PE = -\frac{G M m}{r} \] where \( G \) is the gravitational constant, \( M \) is the mass of the Earth, and \( r \) is the distance from the center of the Earth to the satellite. ### Step 2: Total Energy in Orbit The total mechanical energy \( E \) of the satellite in orbit is the sum of its kinetic and potential energy: \[ E = KE + PE = \frac{1}{2} m v^2 - \frac{G M m}{r} \] ### Step 3: Escape Velocity The escape velocity \( v_e \) from the gravitational field is given by: \[ v_e = \sqrt{\frac{2GM}{r}} \] ### Step 4: Orbital Velocity The orbital velocity \( v_i \) of the satellite in a circular orbit is given by: \[ v_i = \sqrt{\frac{GM}{r}} \] ### Step 5: Relationship Between Escape Velocity and Orbital Velocity From the equations for escape velocity and orbital velocity, we can see that: \[ v_e = \sqrt{2} v_i \] ### Step 6: Calculate the Required Increase in Speed To find the increase in speed required, we calculate: \[ \Delta v = v_e - v_i = \sqrt{2} v_i - v_i = (\sqrt{2} - 1) v_i \] ### Step 7: Calculate the Percentage Increase The percentage increase in speed is given by: \[ \text{Percentage Increase} = \frac{\Delta v}{v_i} \times 100 = \frac{(\sqrt{2} - 1) v_i}{v_i} \times 100 = (\sqrt{2} - 1) \times 100 \] ### Step 8: Numerical Calculation Calculating \( \sqrt{2} \): \[ \sqrt{2} \approx 1.414 \] Thus, \[ \text{Percentage Increase} = (1.414 - 1) \times 100 \approx 0.414 \times 100 \approx 41.4\% \] ### Final Answer The speed of the satellite must be increased by approximately **41.4%** to escape from the gravitational field of the Earth. ---
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