The mean radius of earth is R, its angular speed on its own axis is `omega` and the acceleration due to gravity at earth's surface is g. What will be the radius of the orbit of a geostationary satellite
(a) `((R^(2)g)/(omega^(2)))^(1//3)` (b) `((Rg)/(omega^(2)))^(1//3)` (c) `((R^(2)omega^(2))/(g))^(1//3)` (d) `((R^(2)g)/(omega))^(1//3)`

Options

A. `((Rg)/(omega^(2)))^(1//3)`
B. ` ((R^(2)g)/(omega^(2)))^(1//3)`
C. ` ((R^(2)g)/omega)^(1//3)`
D. `((R^(2)omega^(2))/g)^(1//3)`

Answer

B