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If gravitational field Intensity is E a...

If gravitational field Intensity is E at distance R/2 outside from then surface of a thin shell of radius R , the gravitational field intensity at distance R/2 from its centre is

A

Zero

B

2E

C

`(2E)/3`

D

`(3E)/2`

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The correct Answer is:
To solve the problem, we need to determine the gravitational field intensity at a distance \( \frac{R}{2} \) from the center of a thin spherical shell of radius \( R \), given that the gravitational field intensity is \( E \) at a distance \( \frac{R}{2} \) outside the surface of the shell. ### Step-by-Step Solution: 1. **Understand the Setup**: - We have a thin spherical shell of radius \( R \). - The gravitational field intensity \( E \) is given at a distance \( \frac{R}{2} \) outside the shell. This means the distance from the center of the shell to this point is \( R + \frac{R}{2} = \frac{3R}{2} \). 2. **Apply Gauss's Law for Gravitation**: - According to Gauss's law for gravitation, the gravitational field intensity \( g \) at a distance \( r \) from the center of a spherical shell is given by: \[ g = -\frac{G M}{r^2} \] - However, this applies only outside the shell. Inside the shell, the gravitational field intensity behaves differently. 3. **Evaluate the Gravitational Field Inside the Shell**: - For a hollow thin spherical shell, the gravitational field inside the shell (at any point within the shell) is zero. This is a result of the symmetry of the shell and can be derived from Gauss's law: - If we consider a Gaussian surface inside the shell, the mass enclosed by this surface is zero since all the mass is on the shell's surface. - Thus, by Gauss's law: \[ \oint \vec{E} \cdot d\vec{A} = -4\pi G M_{\text{enclosed}} = 0 \] - This implies that the gravitational field intensity \( E \) inside the shell is zero. 4. **Conclusion**: - Therefore, at a distance \( \frac{R}{2} \) from the center of the shell, the gravitational field intensity is: \[ E_{\text{inside}} = 0 \] ### Final Answer: The gravitational field intensity at a distance \( \frac{R}{2} \) from the center of the shell is **0**.
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