A small hollow sphere which has a small hole in it is immersed in water to a depth of 40 cm, before any water is penetrated into it. If the surface tensionof water si `0.073 Nm^(-1)`, find the radius of the hole.

Explanation

To find the radius of the hole in the small hollow sphere immersed in water, we can use the relationship between surface tension, pressure difference, and the radius of the hole. Here are the steps to solve the problem:

### Step-by-Step Solution

1. **Identify the Given Values**:
- Depth of immersion, \( h = 40 \, \text{cm} = 0.40 \, \text{m} \)
- Surface tension of water, \( T = 0.073 \, \text{N/m} \)
- Density of water, \( \rho = 1000 \, \text{kg/m}^3 \)
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