Home
Class 12
PHYSICS
Suppose that on a temperature scale X, w...

Suppose that on a temperature scale X, water boils af -`60^(@)`X and freezes ar-`180.5^(@)` X What would a temperature of 350 K be on the X-scale?

Text Solution

AI Generated Solution

To find the temperature on the X-scale corresponding to 350 K, we will use the concept of thermometry, which relates temperatures on different scales. ### Step-by-Step Solution: 1. **Identify the boiling and freezing points of water on the X-scale:** - Boiling point of water (T_b) = -60°X - Freezing point of water (T_f) = -180.5°X ...
Promotional Banner

Topper's Solved these Questions

  • THERMAL PROPERTIES OF MATTER

    AAKASH INSTITUTE ENGLISH|Exercise Try Youself|16 Videos

  • THERMAL PROPERTIES OF MATTER

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section-A) Objective Type questions (one option is correct)|50 Videos

  • TEST2

    AAKASH INSTITUTE ENGLISH|Exercise EXERCISE|2 Videos

  • THERMODYNAMICS

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (SECTION -D) (Assertion - Reason Type Questions)|10 Videos

Similar Questions

Explore conceptually related problems

On an X temperature scale, water freezes at -125.0^(@) X and boils at 375.0^(@) X . On a Y temperature scale, water freezes at -70.0^(@)Y and boils at -30.0^(@)Y . The value of temperature on X-scale equal to the temperature of 50.0^(@)Y on Y-scale is

Water freezes at 32^@ F What will be the temperature in degree Celsius and K

The 2.0 Omega resistor show in figure is dipped into a calorimeter containing water. The heat capacity of the calorimeter together with water is 2000 J K^(-1) . (a) If the circuit is active for 15 minutes, what would be the rise in the temperature of the water? (b) Suppose the 6.0 Omega resistor gets burnt. What would be the rise in the temperature of the water in the next 15 minutes? (Figure)

In a termperature scale X ice point of water is assigned a value of 20^(@) X and the boiling point of water is assiggned a value of 220^(@) X . In another scale Y the ice poiny of water is assigned a value of -20^(@) Y and the boiling point is given a value of 380^(@)Y . Then temperature on both the scales will be same is

A certain solution of benzoic acid in benzene boil at 82.6^(@)C and freezes at 3.1^(@)C . What information about the no of particiles and the structure of benzoic acid at the two temperature can be deduced from the above data ? The boiling point and freezing point of pure benzene are 180.1^(@)C and 5.5^(@)C respectively. K_(r)=5.12 k kg//"mol", k_(b)=2.67 k kg/ mol.

On a new scale of temperature (which is linear) and called the W scale. The freezing and boiling points of water are 39^(@)W and 239^(@)W respectively. What will be the temperature on the new scale, corresponding to a temperature of 39^(@)C on the Celsius scale?

On a new scale of temperature (which is linear) and called the W scale. The freezing and boiling points of water are 39^(@)W and 239^(@)W respectively. What will be the temperature on the new scale, corresponding to a temperature of 39^(@)C on the Celsius scale?

The linear equation that converts Fahrenheit (F) to Celsius (C ) is given by the relation, C=(5F-160)/(9) . (i) If the temperature is 86^(@) F , what is the temperature in Celsius ? (ii) If the temperature is 35^(@) C, what is the temperature in Fahrenheit ? (iii) If the temperature is 0^(@) C, what is the temperature in Fahrenheit and if the temperature is 0^(@) F, what is the temperature in Celsius ? (iv) What is the numerical value of the temperature which is same in both the scales ?

The figure shows three temperature scales with the freezing and boiling points of water indicated. (a) Rank the size of a degree on these scales, greatest first. (b) Rank the following temperatures, highest first :50^(@)X,50^(@)W and 50^(@)Y .

Liquid oxygen freezes at - 218.4 ^(@)C and boils at - 183^(@)C . Express these temperatures in Fahrenheit scale.