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The following observation were recorded ...

The following observation were recorded on a platinum resistance thermometer. Resistance at melting point of ice is `=3.70 Omega,` resistance at boiling point of water at normal pressure is`=4.71 Omega,` and resistance at `t^(@)C=5.29Omega.` Calculate
Temperature coefficient of resistance of platinum.
Value of temperature t.

Text Solution

Verified by Experts

(i) Temperature coefficient of resistance ius given by
`aplha=(R_100-R_0)/(R_0xx100)=(4.71-3.70)/(3.70xx100)`
`(1.01)/(370)=2.73xx10^(-3)per"^(C )`
For temperature t we have
`t=100"^(@)Cxx(R_1-R_0)/(R_100-R_0)`
`100"^(@)Cxx(5.29-3.70)/(4.71-3.70)=100"^(@)Cxx(1.59)/(1.01)=157.4"^(@)C`
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