For Question , calculat the block's speed asit passes through the equilibrium point ?
Hint `: E = K+U = (1)/(2) mv^(2) + (1)/(2) kx^(2) = (1)/(2) mv^(2) +0` . Calculate v

Explanation

To calculate the block's speed as it passes through the equilibrium point, we can use the principle of conservation of energy. The total mechanical energy (E) in a simple harmonic oscillator is the sum of kinetic energy (K) and potential energy (U).

### Step-by-Step Solution:

1. **Understanding the Energy Conservation**:
The total mechanical energy in the system is constant and can be expressed as:
\[
E = K + U
...