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For examples , find the potential energy...

For examples , find the potential energy of the block at 0.05 m from the mean position

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To find the potential energy of a block at a distance of 0.05 m from the mean position in a spring-mass system, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the System**: We have a spring-mass system where a block of mass \( m \) is attached to a spring with spring constant \( k \). The block is displaced from the mean position by \( x = 0.05 \, \text{m} \). 2. **Understand the Potential Energy Formula**: ...
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If force constant = 100 N/m, find the potential energy of the block at 0.05 m from the mean position Hint : P.E. = (1)/(2) kx^(2)

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Define potential energy with an example.

A block of mass m = 2 kg is attached to two unstretched spring of force constant k_(1)=100 N//m and k_(2)=125 N//m The block is displaced towards left through a distance of 10 cm and released. Find the speed of the block as it passes through the mean position.

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For any S.H.M., amplitude is 6 cm . If instantaneous potential energy is half the total energy then distance of particle from its mean position is

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