A simple pendulum with a metallic bob has a time period T.The bob is now immersed in a non-viscous liquid and oscillated . If the density of the liuid is `(1)/(4)` that of metal , what will be the time period of the same pendulum?
Hint `:` If the solid bob of the pendulum has relative densty D and has been submerged in a non-viscous liquid of relative density `rho` then effective acceleration due to gravity `g' = g-(g)/(n) ` where `n = (D)/( rho)`

Explanation

If the solid bob of the pendulum has relative densty D and has been submerged in in a non-viscous liquid of relative density `rho` then effective acceleration due to gravity `g. = g-(g)/(n) ` where `h = (D)/( rho)`
So , time period , T. = `2pi sqrt((L)/(g - (g)/(n)))`