A mass is suspended separately by two springs of spring constant `k_(1)` and `k_(2)` in successive order. The time period of oscillations in the two cases are `T_(1)` and `T_(2)` respectively .If the same mass be suspended by connecting the two springs in parallel, (as shown in figure ) then the timer period of oscillations is T. The correct relation is

Options

A. `t_(0)^(2) = t_(1)^(2) + t_(2)^(2)`
B. `t_(0)^(-2) = t_(1)^(-2) + t_(2)^(-2)`
C. `t_(0)^(-2) = t_(1)^(-1) + t_(2)^(-1)`
D. `t_(0) = t_(1) + t_(2)`

Answer

B