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what is the nuclear radius of .^(125)...

what is the nuclear radius ` of .^(125)` Fe , if that of `"".^(27) Al `is 6.4 fermi?

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`R=R_0A^(1//3)`
`(R_(Fe))/(R_(AI))=((A_(Fe))/(A_(AI)))^(1//3) =((125)/(27))^(1//3)`
`R_(Fe)=5/3R_(AI)=5/3xx3.6 =6.0 ` fermi
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