Home
Class 12
PHYSICS
A deutron strikes .8O^16 nucleus with th...

A deutron strikes `._8O^16` nucleus with the subsequent emission of an `alpha`-particle. Find the atomic number, mass number and chemical name of the element so produced.

Text Solution

Verified by Experts

The nuclear reaction may be expressed as under
`""_8O^(16) +""_1H^2 to ""_zX^A+""_2He^4(alpha-"particle")`
Law of conservation of charge 8+1=Z+2 `rArr Z=7`
The atomic number of the element is 7 `rArr` element is nitrogen
Law of conservation of mass number `16+2 =A+4 rArr A=14`
`""_zX^A=""_7N^(14)`
Promotional Banner

Topper's Solved these Questions

  • NUCLEI

    AAKASH INSTITUTE ENGLISH|Exercise Try Yourself|36 Videos
  • NUCLEI

    AAKASH INSTITUTE ENGLISH|Exercise Assignment Section A Objective (One option is correct )|52 Videos
  • MOVING CHARGES AND MAGNETISM

    AAKASH INSTITUTE ENGLISH|Exercise Assignment Section J (Aakash Challengers Questions)|5 Videos
  • OSCILLATIONS

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (Section D) (ASSERTION-REASON TYPE QUESTIONS)|13 Videos

Similar Questions

Explore conceptually related problems

A deuteron strikes ""._(7) N^(14) nucles with the subsequent emission of an alpha -particle ,Find the atomic number , Mass number and chemical name of the element so produced

A deutron strikes ._8 O^16 nucleus with subsequent emission of an alpha particle. Idenify the nucleus so produced.

A neutron is absorbed by a ._(3)^(6)Li nucleus with the subsequent emission of an alpha particle. (i) Write the corresponding nuclear reaction. (ii) Calculate the energy released, in MeV , in this reaction. [Given: mass ._(3)^(6)Li=6.015126u , mass (neutron) =1.0086654 u mass (alpha particle) =4.0026044 u and mass (triton) =3.010000 u . Take i u=931 MeV//c^(2) ]

After the emission of alpha -particle from the atom X_92^238 , the number of neutrons in the atom will be

A radium Ra_88^224 isotope, on emission of an alpha -particle gives rise to a new element whose mass number and atomic number will be:

The emission of an alpha- particle reduces the mass of nuclei by 4 units and increases its atomic number by 2.

An atom of mass number 15 and atomic number 7 captures an alpha- particle and then emits a proton. The mass number and atomic number of the resulting product will respectively be.

Th^(234) disintegrates and emits 6beta- and 7alpha- particles to form a stable product. Find the atomic number and mass number of the stable product and also identify the element.

In the disintegration of a radioactive element, alpha - and beta -particles are evolved from the nucleus. ._(0)n^(1) rarr ._(1)H^(1) + ._(-1)e^(0) + Antineutrino + Energy 4 ._(1)H^(1) rarr ._(2)He^(4) + 2 ._(+1)e^(0) + Energy Then, emission of these particles changes the nuclear configuration and results into a daughter nuclide. Emission of an alpha -particles results into a daughter element having atomic number lowered by 2 and mass number by 4, on the other hand, emission of a beta -particle yields an element having atomic number raised by 1. During beta -decay, the mass of atomic nucleus

A uranium nucleus ._(92)U^(238) emits and alpha -particle and a beta -particle in succession. The atomic number and mass number of the final nucleus will be