The nuclei `""_6A^(13) and ""_7B^(14)` can be described as

Options

A. isotones
B. isobars
C. isotopes of carbon
D. isotopes of nitrogen

Answer

To solve the problem, we need to analyze the given nuclei \( _6A^{13} \) and \( _7B^{14} \) in terms of their atomic numbers and mass numbers.

### Step-by-Step Solution:

1. **Identify the Nuclei**:
- The first nucleus is \( _6A^{13} \), which has an atomic number of 6 (indicating it has 6 protons) and a mass number of 13.
- The second nucleus is \( _7B^{14} \), which has an atomic number of 7 (indicating it has 7 protons) and a mass number of 14.

2. **Check for Isobars**:
- Isobars are nuclei that have the same mass number but different atomic numbers.
- Here, the mass numbers are 13 and 14, which are different. Therefore, \( _6A^{13} \) and \( _7B^{14} \) are **not isobars**.

3. **Check for Isotopes**:
- Isotopes are nuclei that have the same atomic number but different mass numbers.
- The atomic numbers are 6 and 7, which are different. Therefore, \( _6A^{13} \) and \( _7B^{14} \) are **not isotopes**.

4. **Calculate Neutron Numbers**:
- For nucleus \( _6A^{13} \):
- Neutron number = Mass number - Atomic number = \( 13 - 6 = 7 \).
- For nucleus \( _7B^{14} \):
- Neutron number = Mass number - Atomic number = \( 14 - 7 = 7 \).

5. **Conclusion**:
- Both nuclei have the same neutron number (7). Nuclei that have the same number of neutrons but different numbers of protons are called **isotones**.
- Therefore, \( _6A^{13} \) and \( _7B^{14} \) can be described as **isotones**.

### Final Answer:
The nuclei \( _6A^{13} \) and \( _7B^{14} \) can be described as **isotones**.