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90% of the active nuclei present in a ra...

`90%` of the active nuclei present in a radioactive sample are found to remain undecyayed after `1` day. The precentage of undecayed nuclei left after two days will be

A

0.81

B

0.19

C

0.2

D

1

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The correct Answer is:
To solve the problem, we need to determine the percentage of undecayed nuclei left after two days, given that 90% of the active nuclei remain undecayed after one day. We can follow these steps: ### Step 1: Understand the initial condition Let the initial number of active nuclei at time \( t = 0 \) be \( N_0 \). After one day, 90% of these nuclei remain undecayed. Therefore, the number of undecayed nuclei after one day is: \[ N_1 = 0.9 N_0 \] ### Step 2: Use the decay formula The number of undecayed nuclei at any time \( t \) can be expressed using the exponential decay formula: \[ N_t = N_0 e^{-\lambda t} \] where \( \lambda \) is the decay constant. ### Step 3: Set up the equation for one day For \( t = 1 \) day, we can write: \[ N_1 = N_0 e^{-\lambda \cdot 1} \] Substituting the value of \( N_1 \) from Step 1: \[ 0.9 N_0 = N_0 e^{-\lambda} \] ### Step 4: Simplify the equation Dividing both sides by \( N_0 \) (assuming \( N_0 \neq 0 \)): \[ 0.9 = e^{-\lambda} \] ### Step 5: Find the expression for \( e^{-\lambda} \) Taking the natural logarithm of both sides, we can express \( \lambda \): \[ -\lambda = \ln(0.9) \] Thus, \[ \lambda = -\ln(0.9) \] ### Step 6: Calculate the number of undecayed nuclei after two days Now, we need to find the number of undecayed nuclei after two days (\( t = 2 \)): \[ N_2 = N_0 e^{-\lambda \cdot 2} \] Substituting \( \lambda \): \[ N_2 = N_0 e^{-2(-\ln(0.9))} = N_0 e^{2\ln(0.9)} = N_0 (e^{\ln(0.9)})^2 = N_0 (0.9^2) \] ### Step 7: Calculate \( 0.9^2 \) Calculating \( 0.9^2 \): \[ 0.9^2 = 0.81 \] Thus, the number of undecayed nuclei after two days is: \[ N_2 = 0.81 N_0 \] ### Step 8: Find the percentage of undecayed nuclei To find the percentage of undecayed nuclei left after two days, we can express it as: \[ \text{Percentage undecayed} = \left( \frac{N_2}{N_0} \right) \times 100 = 0.81 \times 100 = 81\% \] ### Final Answer The percentage of undecayed nuclei left after two days is **81%**. ---
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