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The decay constant of a radioactive isot...

The decay constant of a radioactive isotope is `lambda`. If `A_1` and `A_2` are its activites at time `t_1` and `t_2` respectively, then the number of nuclei which have decayed the time `(t_1-t_2)`

A

`A_1t_1-A_2t_2`

B

`A_1-A_2`

C

`(A_1-A_2)//lambda`

D

`lambda(A_1-A_2)`

Text Solution

Verified by Experts

The correct Answer is:
C
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