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In a radioactive material the acticity a...

In a radioactive material the acticity at time `t_(1)` is `R_(1)` and at a later time `t_(2)`, it is `R_(2)`. If the decay constant of the material is `lambda`, then

A

`R_1-R_2e^((-lambda(t_1-t_2)))`

B

`R_1=R_2e^((lambda(t_1-t_2)))`

C

`R_1=R_2((t_2)/(t_1))`

D

`R_1=R_2`

Text Solution

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The correct Answer is:
A
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