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The binding energies per nucleon for a d...

The binding energies per nucleon for a deuteron and an `alpha-`particle are `x_1` and `x_2` respectively. What will be the energy `Q` released in the following reaction ?
`._1H^2 + ._1H^2 rarr ._2He^4 + Q`.

A

`4(x_1+x_2)`

B

`4(x_2-x_1)`

C

`2(x_2-x_1)`

D

`2(x_1+x_2)`

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The correct Answer is:
To find the energy \( Q \) released in the reaction \( _1H^2 + _1H^2 \rightarrow _2He^4 + Q \), we will follow these steps: ### Step 1: Understand the reaction The reaction involves two deuterium nuclei (\( _1H^2 \)) fusing to form an alpha particle (\( _2He^4 \)). We need to calculate the energy released during this fusion process. ### Step 2: Define binding energy per nucleon Binding energy per nucleon is the energy required to remove a nucleon from a nucleus. For the deuteron, the binding energy per nucleon is denoted as \( x_1 \), and for the alpha particle, it is denoted as \( x_2 \). ### Step 3: Calculate total binding energy for reactants and products - The total binding energy of the two deuterons (reactants) can be calculated as: \[ \text{Total Binding Energy of Reactants} = 2 \times x_1 \] (since each deuteron has 2 nucleons). - The total binding energy of the alpha particle (product) is: \[ \text{Total Binding Energy of Products} = 4 \times x_2 \] (since the alpha particle has 4 nucleons). ### Step 4: Calculate the energy released \( Q \) The energy released in the reaction is equal to the difference in binding energy between the reactants and the products: \[ Q = \text{Total Binding Energy of Products} - \text{Total Binding Energy of Reactants} \] Substituting the values we calculated: \[ Q = (4 \times x_2) - (2 \times x_1) \] Rearranging gives: \[ Q = 4x_2 - 2x_1 \] ### Step 5: Final expression for \( Q \) Since energy is released, we can express this as: \[ Q = 2(x_2 - x_1) \] ### Conclusion The energy \( Q \) released in the fusion of two deuterons to form an alpha particle is given by: \[ Q = 2(x_2 - x_1) \]
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