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For the reaction, 2N2O5rarr4NO2+O2 S...

For the reaction,
`2N_2O_5rarr4NO_2+O_2`
Select the correct statement

A

Rate of formation of `O_2` is same as rate of formation of `NO_2`

B

Rate of disappearance of `N_2O_5` is two times the rate of formation of `NO_2`

C

Rate of formation of `O_2` is 0.5 time rate disappearance of `N_2O_5`

D

Rate of formation of `NO_2` is equal to rate of disappearance of `N_2O_5`

Text Solution

AI Generated Solution

The correct Answer is:
To analyze the reaction \( 2N_2O_5 \rightarrow 4NO_2 + O_2 \) and select the correct statement regarding the rates of formation and disappearance of the substances involved, we can follow these steps: ### Step 1: Write the rate expressions for the reaction. For the reaction \( 2N_2O_5 \rightarrow 4NO_2 + O_2 \), we can express the rates of disappearance of the reactant and the rates of formation of the products as follows: - The rate of disappearance of \( N_2O_5 \): \[ -\frac{1}{2} \frac{d[N_2O_5]}{dt} \] - The rate of formation of \( NO_2 \): \[ \frac{1}{4} \frac{d[NO_2]}{dt} \] - The rate of formation of \( O_2 \): \[ \frac{1}{1} \frac{d[O_2]}{dt} \] ### Step 2: Relate the rates of formation and disappearance. From the stoichiometry of the reaction, we can relate these rates: 1. The rate of formation of \( NO_2 \) is related to the rate of disappearance of \( N_2O_5 \): \[ -\frac{1}{2} \frac{d[N_2O_5]}{dt} = \frac{1}{4} \frac{d[NO_2]}{dt} \] 2. The rate of formation of \( O_2 \) is also related to the rate of disappearance of \( N_2O_5 \): \[ \frac{1}{1} \frac{d[O_2]}{dt} = -\frac{1}{2} \frac{d[N_2O_5]}{dt} \] ### Step 3: Analyze the statements. Now we can analyze the statements provided: 1. **Statement 1**: The rate of formation of \( O_2 \) is the same as the rate of formation of \( NO_2 \). - This is incorrect because the rate of formation of \( O_2 \) is \( 0.5 \) times the rate of formation of \( NO_2 \). 2. **Statement 2**: The rate of disappearance of \( N_2O_5 \) is \( 2 \) times the rate of formation of \( NO_2 \). - This is incorrect because the rate of disappearance of \( N_2O_5 \) is \( 2 \) times the rate of formation of \( O_2 \), not \( NO_2 \). 3. **Statement 3**: The rate of formation of \( O_2 \) is \( 0.5 \) times the rate of disappearance of \( N_2O_5 \). - This is correct as derived from the rate expressions. 4. **Statement 4**: The rate of formation of \( NO_2 \) is equal to the rate of disappearance of \( N_2O_5 \). - This is incorrect because the rate of formation of \( NO_2 \) is \( 2 \) times the rate of disappearance of \( N_2O_5 \). ### Conclusion The correct statement is **Statement 3**: The rate of formation of \( O_2 \) is \( 0.5 \) times the rate of disappearance of \( N_2O_5 \). ---
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AAKASH INSTITUTE ENGLISH-CHEMICAL KINETICS-EXERCISE
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  2. The unit of rate and rate constant are same for a

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  3. For the reaction, 2N2O5rarr4NO2+O2 Select the correct statement

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  4. The rate constant of n^(th) order has units :

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  8. if the rate of a reaction is equal to the rate constant , the ...

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  10. The rate constatnt depends on

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  11. 2A rarrC+D In this reaction, if we double the concentration of A, re...

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  12. In a zero order reaction , 20% of the reaction complete in 10 s. How m...

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  13. If the half - life of the first order reaction is 50 s, what be the va...

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  14. In a first order reaction , on plotting a graph between t(1//2) and co...

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  15. In data given below. {:(,[A],[B],"rate"),(,mol//L,mol//L,mol L ^(-1...

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  16. For certain first order reaction, 75% of the reaction complete in 30 m...

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  17. For zero order reaction , t(1//2) will be (A0 is the initial concentra...

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