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For the reaction N(2) to 3H(2) to 2NH(3)...

For the reaction `N_(2) to 3H_(2) to 2NH_(3)`, how are the rate of reaction expressions inter-related `(d[H_(2)])/(dt)` and `(d[NH_(3)])/(dt)`?

A

`(d[NH_3])/(dt)=-1/3(d[H_2])/(dt)`

B

`+(d[NH_3])/(dt)=-2/3(d[H_2])/(dt)`

C

`+(d[NH_3])/(dt)=-3/2(d[H_2])/(dt)`

D

`(d[NH_3])/(dt)=(d[H_2])/(dt)`

Text Solution

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The correct Answer is:
B
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