Suppose a pure Si-crystal has `6xx10^(28) "atoms" m^(-3)`. It is doped by 1 ppm concentration of pentavalent As. Calculate the number of electrons and holes. Give that `n_(i)=1.5xx10^(16)m^(-3)`.

Explanation

To solve the problem step by step, we will follow these calculations:

### Step 1: Calculate the number of dopant atoms
Given that the concentration of silicon atoms is \( n = 6 \times 10^{28} \, \text{atoms/m}^3 \) and the doping concentration is 1 ppm (parts per million), we can calculate the number of pentavalent arsenic (As) atoms doped in the silicon crystal.

\[ \text{Number of dopant atoms} = n \times \frac{1 \, \text{ppm}}{10^6} = 6 \times 10^{28} \times \frac{1}{10^6} = 6 \times 10^{22} \, \text{atoms/m}^3 \]
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