Calculate the current l in the following circuit, if all the diodes are ideal. All resistances are `200 Omega`

Options

A. Zero
B. `1 A`
C. `2 A`
D. `4 A`

Answer

To calculate the current \( I \) in the given circuit with ideal diodes and resistances of \( 200 \, \Omega \), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Circuit Configuration**:
- The circuit consists of multiple branches with diodes and resistors. The resistors are all \( 200 \, \Omega \), and we have a voltage supply of \( 200 \, V \).

2. **Determine the State of the Diodes**:
- Since the diodes in branches GH and CD are reverse-biased, they do not conduct current. Therefore, we can ignore these branches for the current calculation.
- The only branch that conducts current is branch EF, where the diode is forward-biased.

3. **Apply Ohm's Law**:
- Ohm's Law states that \( V = I \times R \), where \( V \) is voltage, \( I \) is current, and \( R \) is resistance.
- We will use this law to find the current through the conducting branch (EF).

4. **Calculate the Current**:
- The voltage across the conducting branch EF is \( 200 \, V \).
- The resistance in this branch is \( 200 \, \Omega \).
- Using Ohm's Law, we can rearrange it to find the current:
\[ I = \frac{V}{R} = \frac{200 \, V}{200 \, \Omega} = 1 \, A \]

5. **Conclusion**:
- The current \( I \) in the circuit is \( 1 \, A \).

### Final Answer:
The current \( I \) in the circuit is \( 1 \, A \).