In a transitor `(Beta = 50)`, the voltage across `5 kOmega` load resistance in collector circuit is `5V`. The base current is

Options

A. `0.02 mA`
B. `0.03 mA`
C. `0.08 mA`
D. `0.09 mA`

Answer

To find the base current (Ib) in the transistor, we can follow these steps:

### Step 1: Identify the given values
- Beta (β) = 50
- Load resistance (RL) = 5 kΩ = 5 × 10^3 Ω
- Voltage across the load resistance (Vc) = 5 V

### Step 2: Calculate the collector current (Ic)
The collector current (Ic) can be calculated using Ohm's law:
\[ Ic = \frac{Vc}{RL} \]

Substituting the values:
\[ Ic = \frac{5 \, V}{5 \times 10^3 \, \Omega} \]
\[ Ic = \frac{5}{5000} \]
\[ Ic = 0.001 \, A \]
\[ Ic = 10^{-3} \, A \]

### Step 3: Relate collector current (Ic) to base current (Ib)
The relationship between collector current (Ic) and base current (Ib) is given by the formula:
\[ Ic = β \times Ib \]

### Step 4: Rearrange the formula to find Ib
We can rearrange the formula to find Ib:
\[ Ib = \frac{Ic}{β} \]

### Step 5: Substitute the known values to calculate Ib
Substituting the values we have:
\[ Ib = \frac{10^{-3} \, A}{50} \]
\[ Ib = \frac{10^{-3}}{50} \]
\[ Ib = 0.02 \times 10^{-3} \, A \]
\[ Ib = 20 \times 10^{-6} \, A \]
\[ Ib = 20 \, \mu A \]

### Final Answer
The base current (Ib) is **20 μA**.

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