The current in the circuit will be

Options

A. `5/10 A`
B. `5/50 A`
C. `5/10` A
D. `5/20` A

Answer

To find the current in the given circuit, we can follow these steps:

### Step 1: Identify the Components
We have the following components in the circuit:
- A voltage supply of \( V = 5 \, \text{V} \)
- A resistor \( R_1 = 20 \, \Omega \) in series
- A diode \( D_1 \) which is in forward bias
- A diode \( D_2 \) which is in reverse bias
- A resistor \( R_2 = 30 \, \Omega \) connected with \( D_2 \)

### Step 2: Determine the State of the Diodes
- Since \( D_1 \) is in forward bias, it will allow current to flow through it.
- Since \( D_2 \) is in reverse bias, it will not allow current to flow through it.

### Step 3: Calculate the Total Resistance
The total resistance in the circuit will only include the resistors that are in the path of the current. Since \( D_2 \) is reverse biased, we only consider \( R_1 \) and \( R_2 \) (which is effectively not contributing to the circuit due to the reverse bias of \( D_2 \)):
- \( R_{\text{equivalent}} = R_1 + R_2 = 20 \, \Omega + 30 \, \Omega = 50 \, \Omega \)

### Step 4: Apply Ohm's Law to Find the Current
Using Ohm's Law, which states that \( I = \frac{V}{R} \):
- Here, \( V = 5 \, \text{V} \) and \( R = R_{\text{equivalent}} = 50 \, \Omega \)
- Therefore, the current \( I \) can be calculated as:
\[ I = \frac{5 \, \text{V}}{50 \, \Omega} = \frac{5}{50} = 0.1 \, \text{A} = 10 \, \text{mA} \]

### Conclusion
The current flowing through the circuit is \( 0.1 \, \text{A} \) or \( 10 \, \text{mA} \).

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