Home
Class 12
PHYSICS
If the planes of two identical concentri...

If the planes of two identical concentric coils are perpendicular and the magnetic moment of each coil is M, then the resultant magnetic moment of the two coils wil be

A

M

B

2M

C

3M

D

`sqrt(2)M`

Text Solution

AI Generated Solution

The correct Answer is:
To find the resultant magnetic moment of two identical concentric coils whose planes are perpendicular to each other, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Magnetic Moments**: Let the magnetic moment of each coil be denoted as \( m \). Therefore, for the first coil, we have: \[ m_1 = m \] and for the second coil: \[ m_2 = m \] 2. **Determine the Angle Between the Coils**: Since the planes of the two coils are perpendicular to each other, the angle \( \theta \) between the magnetic moments of the two coils is: \[ \theta = 90^\circ \] 3. **Use the Formula for Resultant Magnetic Moment**: The resultant magnetic moment \( m_{\text{net}} \) for two vectors (in this case, the magnetic moments of the coils) that are at an angle \( \theta \) is given by: \[ m_{\text{net}} = \sqrt{m_1^2 + m_2^2 + 2 m_1 m_2 \cos(\theta)} \] Since \( \theta = 90^\circ \), we have \( \cos(90^\circ) = 0 \). Thus, the formula simplifies to: \[ m_{\text{net}} = \sqrt{m_1^2 + m_2^2} \] 4. **Substituting the Values**: Substituting \( m_1 = m \) and \( m_2 = m \) into the equation, we get: \[ m_{\text{net}} = \sqrt{m^2 + m^2} = \sqrt{2m^2} \] 5. **Simplifying the Result**: Taking the square root, we find: \[ m_{\text{net}} = \sqrt{2} m \] ### Final Result: Thus, the resultant magnetic moment of the two coils is: \[ m_{\text{net}} = \sqrt{2} m \] ### Conclusion: The correct answer is \( \sqrt{2} m \). ---
Promotional Banner

Topper's Solved these Questions

  • MOVING CHARGE AND MAGNESIUM

    AAKASH INSTITUTE ENGLISH|Exercise SECTION C|47 Videos
  • MOVING CHARGE AND MAGNESIUM

    AAKASH INSTITUTE ENGLISH|Exercise SECTION D|16 Videos
  • MOVING CHARGE AND MAGNESIUM

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (SECTION A)|34 Videos
  • MOTION IN STRAIGHT LINE

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (SECTION - J)|2 Videos
  • MOVING CHARGES AND MAGNETISM

    AAKASH INSTITUTE ENGLISH|Exercise Assignment Section J (Aakash Challengers Questions)|5 Videos

Similar Questions

Explore conceptually related problems

A circular coil of Radius R is folded across its diameter such that the planes of two half rings are perpendicular to each other as shown in the figure. If the current through the coil is calculate the magnetic dipole moment of the configuration so formed.

Two identical coils have· a common centre and their planes are at right angles to each other and carry equal currents. If the magnitude of the induction field at the centre due to one of the coil is 'B ', then the resultant magnetic induction field due to combination at their common centre is

In the question number 73, for the coil given the magnetic moment is

Two magnets of moment M and 2 M are tied at an angle of 60^(@) to each other . What is the resultant magnetic moment of the combination ?

A bar magnet of magnetic moment 80 units is cut into two halves of equal length, the magnetic moment of each half will be:

Current is flowing in a coil of area A and number of turns N, then magnetic moment of the coil ,M is equal to

Two magnets of equal magnetic moments M each are placed as shown in figure below . The resultant magnetic moment is M . Then value of theta is

A magnet of magnetic moment M amd pole strenth m is divided in two equal parts, then magnetic moment of each part will be

A magnet of magnetic moment M amd pole strenth m is divided in two equal parts, then magnetic moment of each part will be

Two similar coils are kept mutually perpendicular such that their centres coincide. At the centre, find the ratio of the magnetic field due to one coil and the resultant magnetic field by both coils, if the same current is flown

AAKASH INSTITUTE ENGLISH-MOVING CHARGE AND MAGNESIUM-SECTION B
  1. A charged particle enters a uniform magnetic field perpendicular to it...

    Text Solution

    |

  2. A proton and an alpha particle enter the same magnetic field which is ...

    Text Solution

    |

  3. A particle of charge -q and mass m enters a uniform magnetic field B (...

    Text Solution

    |

  4. A proton moving with a constant velocity passes through a region of sp...

    Text Solution

    |

  5. A current I ampere flows in a circular arc of wire whose radius is R,W...

    Text Solution

    |

  6. A current I flows in a thin wire in the shape of a regular polygon n s...

    Text Solution

    |

  7. Two long straight conductors with current I(1) and I(2) are placed alo...

    Text Solution

    |

  8. Surface charge density on a rign of radius a and width d of is sigma a...

    Text Solution

    |

  9. If vecB(1),vecB(2) and vecB(3) are the magnetic field due to l(1),l(2)...

    Text Solution

    |

  10. A uniform conducting wire ABC has a mass of 10g. A current of 2A flows...

    Text Solution

    |

  11. Figure show a conducting loop ADCA carrying current I and placed in a ...

    Text Solution

    |

  12. A wire carrying a current I is placed in a uniform magnetic field in t...

    Text Solution

    |

  13. The magnetic field existing in a region is given by B=B(0)[1+(x)/(...

    Text Solution

    |

  14. Two protons A and B move parallel to the x-axis is opposite directions...

    Text Solution

    |

  15. If the planes of two identical concentric coils are perpendicular and ...

    Text Solution

    |

  16. An electron of charge e is going around in an orbit of radius R meters...

    Text Solution

    |

  17. The phosphor bronze strip is used in a moving coil galvanometer becaus...

    Text Solution

    |