Calculate the maximum kinetic energy of photoelectrons emitted when a light of frequency `2xx10 ^(16)` Hz is irradiated on a metal surface with threshold frequency `(v_0)` equal to `8.68 xx 10^(15)` Hz.

Explanation

To calculate the maximum kinetic energy of photoelectrons emitted when light of a certain frequency is irradiated on a metal surface, we can use the photoelectric equation:

\[ KE = h\nu - h\nu_0 \]

where:
- \( KE \) is the kinetic energy of the emitted photoelectrons,
- \( h \) is Planck's constant (\( 6.626 \times 10^{-34} \, \text{J s} \)),
- \( \nu \) is the frequency of the incident light,
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