The threshold frequency `v_(0)` for a metal is `8 xx 10^(14) s^(-1)`. What is the kinetic energy of an electron emitted having frequency `v=1.0 xx 10^(15) s^(-1)`

Explanation

To find the kinetic energy of an emitted electron when given the threshold frequency and the frequency of the emitted electron, we can use the photoelectric effect equation. Here’s the step-by-step solution:

### Step 1: Understand the given values
- **Threshold frequency (ν₀)** = \(8 \times 10^{14} \, \text{s}^{-1}\)
- **Frequency of emitted electron (ν)** = \(1.0 \times 10^{15} \, \text{s}^{-1}\)

### Step 2: Recall the formula for kinetic energy
The kinetic energy (KE) of an emitted electron can be calculated using the formula derived from the photoelectric effect:
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