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The internuclear distance between two ad...

The internuclear distance between two adjacent atoms of Ne is 360 pm . What will be its van der Waals radius ?

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To find the van der Waals radius of neon (Ne) given the internuclear distance between two adjacent atoms, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Concept of Van der Waals Radius**: - The van der Waals radius is defined as half of the internuclear distance between two non-bonded atoms. It represents the effective size of an atom when it is not bonded to another atom. 2. **Identify the Given Information**: ...
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It is not possible to measure the atomic radius prectsely since the electron cloub surrouding the atom does not have a sharp boundary. One practial approach to estimate the size of an atom of a non-metallic element is to measure the distance between two atoms when they are bound togther by a signle bond in a covalent molecule and then dividing by two. For metals we define the term "matellic radius" which is taken as half the internuclear distance separating the metal cores in the metallic crystal. Then van der waal's radius represents the over all size of the atoms which includes its valence shell in a non bonded situation. It is the half of the distance between two similar atoms in separate molecules in a solid. The atomis radius decreases across a period and increases down the group. Same trends are observed in case of ionic radius. Ionic radius of the species having same number of electrons depends on the number of protons in their nuclei. Sometimes, atomic and ionic radii give unexpected trends due to poor shielding of nuclear charge by d -and f- orbital electrons. Now answer the following three questions: Select the INCORRECT option regarding atomic//ionic sizes:

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It is not possible to measure the atomic radius precisely since the electron cloud surrounding the atom does not have a sharp boundary. One practical approach to estimate the size of an atom of a non-metallic element is to measure the distance between two atoms when they are bound together by a single bond in a covalent molecule and then dividing by two. For metals we define the term "metallic radius" which is taken as half the inter nuclear distance separating the metal cores in the metallic crystal. Then van der waal's radius represents the over all size of the atoms which includes its valence shell in a non bonded situation. It is the half of the distance between two similar atoms in separate molecules in a solid. The atomic radius decreases across a period and increases down the group. Same trends are observed in case of ionic radius. Ionic radius of the species having same number of electrons depends on the number of protons in their nuclei. Sometimes, atomic and ionic radii give unexpected trends due to poor shielding of nuclear charge by d -and f- orbital electrons. Now answer the following three questions: Which of the following relations is correct, if considered for the same element.

It is not possible to measure the atomic radius precisely since the electron cloud surrounding the atom does not have a sharp boundary. One practical approach to estimate the size of an atom of a non-metallic element is to measure the distance between two atoms when they are bound together by a single bond in a covalent molecule and then dividing by two. For metals we define the term "metallic radius" which is taken as half the inter nuclear distance separating the metal cores in the metallic crystal. Then van der waal's radius represents the over all size of the atoms which includes its valence shell in a non bonded situation. It is the half of the distance between two similar atoms in separate molecules in a solid. The atomic radius decreases across a period and increases down the group. Same trends are observed in case of ionic radius. Ionic radius of the species having same number of electrons depends on the number of protons in their nuclei. Sometimes, atomic and ionic radii give unexpected trends due to poor shielding of nuclear charge by d -and f- orbital electrons. Now answer the following three questions: K^(+), CI^(-), Ca^(2+), S^(2-) ions are isoelectronic. The decreasing order of their size is:

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  1. The internuclear distance between two adjacent atoms of Ne is 360 pm ....

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  2. What were the 12 horizontal rows known in the periodic table prepared ...

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  3. Name the German chemist who classified the elements using the physical...

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  4. What would be the IUPAC name and symbol of Bohrium with atomic number ...

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  5. IUPAC symbol of atomic number 119.

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  6. What is the position of lanthanide and actinide series in the periodic...

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  7. How many elements can be there in the third period ?

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  8. Do the non-metallic character exhibited by the halogens have any relat...

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  9. Why s-block elements act as strong reducing agents ?

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  10. Find the position of element with atomic number 35 in the periodic tab...

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  11. What are transuranic elements ?

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  12. Out of the following elements which is the most non-metallic ? Na, M...

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  13. Pick the metalloid among the following given elements. P, S, Si, Al.

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  14. Describe the trend of atomic size along a period and a group in the ...

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  15. What will be the atomic radius of fluorine atom of a covalently bonded...

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  16. The internuclear distance between adjacent chlorine atoms of the two n...

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  17. Arrange the following elements in the order of increasing atomic radiu...

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  18. For which element the second ionization enthalpy is expected to be gre...

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  19. What is the expected order of ionization enthalpy for the given elemen...

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  20. Which among the following elements will have a positive electron gain ...

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  21. S has more negative electron gain enthalpy than O why ?

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