`Delta E and Delta H` both are zero in

Options

A. Isobaric process
B. Adiabatic process
C. Isochoric process
D. Cyclic process

Answer

To determine in which process both ΔE (change in internal energy) and ΔH (change in enthalpy) are zero, we will analyze the four given processes: isobaric, adiabatic, isochoric, and cyclic.

### Step-by-Step Solution:

1. **Understanding the Processes**:
- **Isobaric Process**: This is a process that occurs at constant pressure. In this process, even though the pressure remains constant, there can be changes in internal energy and enthalpy due to heat transfer and work done.
- **Adiabatic Process**: In this process, there is no heat exchange with the surroundings (Q = 0). However, internal energy can change due to work done on or by the system, so ΔE and ΔH are not necessarily zero.
- **Isochoric Process**: This process occurs at constant volume. Since there is no work done (W = 0), any heat added changes the internal energy, thus ΔE is not zero. Consequently, ΔH is also not zero.
- **Cyclic Process**: In a cyclic process, the system returns to its initial state. Since internal energy and enthalpy are state functions, the change in these properties over a complete cycle is zero. Therefore, ΔE = 0 and ΔH = 0.

2. **Analyzing Each Option**:
- **Option A (Isobaric Process)**: ΔE and ΔH are not zero.
- **Option B (Adiabatic Process)**: ΔE and ΔH are not zero.
- **Option C (Isochoric Process)**: ΔE and ΔH are not zero.
- **Option D (Cyclic Process)**: ΔE = 0 and ΔH = 0.

3. **Conclusion**:
- The only process in which both ΔE and ΔH are zero is the **Cyclic Process**.

### Final Answer:
**Option D: Cyclic Process**