The `Delta G` in the process of melting of Ice at `-15^(@) C` is

Options

A. `Delta G lt 0`
B. `Delta G gt 0`
C. `Delta G = 0`
D. All of these

Answer

To find the change in Gibbs free energy (ΔG) for the melting of ice at -15°C, we can follow these steps:

### Step 1: Understand the process
Melting of ice is a phase transition from solid (ice) to liquid (water). This process typically occurs at 0°C (273 K) under standard atmospheric pressure. However, the question specifies that we are considering the melting at -15°C.

**Hint:** Remember that phase transitions have specific temperature points where they are spontaneous.

### Step 2: Determine the spontaneity of the process
At -15°C, which is below 0°C, ice cannot spontaneously melt. This means that the melting of ice at this temperature is a non-spontaneous process.

**Hint:** Recall that spontaneous processes have a negative ΔG, while non-spontaneous processes have a positive ΔG.

### Step 3: Relate ΔG to spontaneity
For a non-spontaneous process, the change in Gibbs free energy (ΔG) is always positive. Therefore, we can conclude that ΔG for the melting of ice at -15°C is greater than zero.

**Hint:** Use the relationship between spontaneity and ΔG to determine the sign of ΔG.

### Step 4: Conclusion
Since melting of ice at -15°C is non-spontaneous, we can conclude that ΔG is positive.

**Final Answer:** ΔG for the melting of ice at -15°C is positive (ΔG > 0).

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