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1/2 F(2)+e^(-) rarr F^(-)" "E^(@)=+3.02V...

`1/2 F_(2)+e^(-) rarr F^(-)" "E^(@)=+3.02V`
Electrode potential for given reaction
`F_(2)+2e^(-) rarr 2F^(-)`

A

3.02 V

B

6.04 V

C

1.5 V

D

`-3.02` V

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The correct Answer is:
A
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